By keeping moment of inertia of a body constant, if we double the time period, then angular momentum of body

Options

A. doubles
B. quadruples
C. remains constant
D. becomes half

Answer

D

Explanation

`L=Iomega=I.(2pi)/(T)`
`therefore" (L_(2))/(L_(1))=(2piI)/(T_(2))xx(T_(1))/(2piI)=(T_(1))/(T_(2))=(T_(1))/(2T_(1))=(1)/(2)`
`therefore L_(2)=(L_(1))/(2)" or L becomes half."`