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The total energy of rolling ring of mass...

The total energy of rolling ring of mass m and radius R is

A

`(3)/(2)mv^(2)`

B

`(1)/(2)mv^(2)`

C

`mv^(2)`

D

`(5)/(2)mv^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E="Translational K.E."+"Rotational K.E."`
`=(1)/(mv^(2))+(1)/(2)Iomega^(2)=(1)/(2)mv^(2)+(1)/(2)mR^(2).(v^(2))/(R^(2))=mv^(2)`
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