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In a CO molecule, the distance between "...

In a CO molecule, the distance between `"C (mass = 12 a.m.u.) and O (mass= 16 a.m.u.), where 1 a.m.u." = (5)/(3)xx10^(-27) kg` , is close to
(Given : `I_(CO) = 1.87 xx 10^(-46) kg m^(2)`)

A

`2.4xx10^(-10)m`

B

`1.9xx10^(-10)m`

C

`1.3xx10^(-10)m`

D

`4.4xx10^(-11)m`

Text Solution

Verified by Experts

The correct Answer is:
C
For the CO molecule, `m_(1) = m_(c )=12`a.m.u
and `m_(2)=m_(0)=16` a.m.u
`therefore` Its reduced mass,
`mu=(m_(1)m_(2))/(m_(1)+m_(2))=(12xx16)/(12+16)`
`=(192)/(28)a.m.u = (48)/(7)a.m.u`
`therefore mu = (48)/(7)xx(5)/(3)xx10^(-27)=(80)/(7)xx10^(-27)`
and the M.I. of the CO molecule is `I = mu^(2)`
`therefore r^(2)=(I)/(mu)=(1.87xx10^(-46)xx10^(-27)xx7)/(80)`
`therefore r^(2)=1.69xx10^(-20) " " therefore r=1.3xx10^(-10)m`
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