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A whel of M.I. = 1 kg-m^(2) is rotatin...

A whel of M.I. = `1 kg-m^(2)` is rotating at an angular speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minute. What is the angular momentum of the wheel in` kg m^(2)//s` two minutes before it comes to rest ?

A

3

B

5

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
`omega_(1)="40 rad/s at t = 0"`
`omega_(0)=0" at t = 10 min = 600 s"`
`omega_(3)=?"at time t' = 8 min = 480 s"`
`omega_(2)=omega_(1)+alphat" "therefore " "0=40+alphaxx600`
`therefore" "alpha=-(40)/(600)=-(1)/(15)"rad/s"^(2)`
and `omega_(3)=omega_(1)+alphat'`
`=40+(-(1)/(15))xx480=40-32="8 rad/s"`
`therefore L=Iomga_(3)=1xx8=8" kg m"^(2)//s`
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