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Show that equation of the circle passing...

Show that equation of the circle passing through the origin and cutting intercepts `a and b` on the coordinate axes is `x^2 + y^2 - ax - by =0`

A

`x^(2) + y^(2) + ax + by = 0 `

B

`x^(2) + y^(2) - ax - by = 0 `

C

` x^(2) + y^(2) - ax + by = 0 `

D

`x^(2)+ y^(2) + bx + ay = 0 `

Text Solution

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The correct Answer is:
B
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