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Equation of circle of radius 5, centred ...

Equation of circle of radius 5, centred on X-axis and touch Y-axis , is

A

`x^(2) + y^(2) pm 5x = 0`

B

`x^(2) + y^(2) pm 5y = 0 `

C

`x^(2) + y^(2) pm 10y = 0 `

D

`x^(2) + y^(2) pm 10x = 0 `

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The correct Answer is:
To find the equation of a circle with a radius of 5, centered on the X-axis, and touching the Y-axis, we can follow these steps: ### Step 1: Understand the properties of the circle The center of the circle lies on the X-axis, which means its y-coordinate is 0. The radius is given as 5, and since the circle touches the Y-axis, the distance from the center to the Y-axis must be equal to the radius.
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