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A circle of radius 2 lies in the first q...

A circle of radius `2` lies in the first quadrant and touches both the axes. Find the equation of the circle with centre at `(6,5)` and touching the above circle externally.

A

`x^(2) + y^(2) + 12x - 10y + 52 = 0 `

B

`x^(2) + y^(2) - 12x - 10y - 52 = 0 `

C

`x^(2) + y^(2) - 12x - 10y + 52 = 0 `

D

`x^(2) + y^(2) + 12x + 10y + 52 = 0 `

Text Solution

Verified by Experts

The correct Answer is:
C
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