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Find the equation of hyperbola where, co...

Find the equation of hyperbola where, conjugate axis is 3 along Y-axis and distance between foci is 5.

A

`(4x^(2))/(9) - (y^(2))/(4) = 1`

B

`(x^(2))/(4) - (4y^(2))/(9) = 1`

C

`(x^(2))/(4) - (y^(2))/(9) = 1`

D

`4x^(2) - 36y^(2) = 9`

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The correct Answer is:
To find the equation of the hyperbola given the conjugate axis and the distance between the foci, we can follow these steps: ### Step 1: Identify the given information - The length of the conjugate axis is 3 along the Y-axis. - The distance between the foci is 5. ### Step 2: Determine the values of \(c\) and \(b\) - The distance between the foci is given by \(2c\). Therefore, we can write: \[ 2c = 5 \implies c = \frac{5}{2} \] - The length of the conjugate axis is given by \(2b\). Thus: \[ 2b = 3 \implies b = \frac{3}{2} \] ### Step 3: Use the relationship between \(a\), \(b\), and \(c\) For hyperbolas, the relationship between \(a\), \(b\), and \(c\) is given by: \[ c^2 = a^2 + b^2 \] Substituting the values of \(c\) and \(b\): \[ \left(\frac{5}{2}\right)^2 = a^2 + \left(\frac{3}{2}\right)^2 \] Calculating \(c^2\) and \(b^2\): \[ \frac{25}{4} = a^2 + \frac{9}{4} \] ### Step 4: Solve for \(a^2\) Rearranging the equation: \[ a^2 = \frac{25}{4} - \frac{9}{4} = \frac{16}{4} = 4 \] Thus, we find: \[ a = 2 \] ### Step 5: Write the equation of the hyperbola Since the conjugate axis is along the Y-axis, the standard form of the hyperbola is: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] Substituting the values of \(a^2\) and \(b^2\): \[ \frac{x^2}{4} - \frac{y^2}{\left(\frac{3}{2}\right)^2} = 1 \] This simplifies to: \[ \frac{x^2}{4} - \frac{4y^2}{9} = 1 \] ### Final Equation The final equation of the hyperbola is: \[ \frac{x^2}{4} - \frac{4y^2}{9} = 1 \] ---
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MARVEL PUBLICATION-CIRCLE AND CONICS -MULTIPLE CHOICE QUESTIONS
  1. If the distance foci of an ellipse is 8 and distance between its dire...

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  2. Find the equation of the hyperbola whole transverse and conjugate axes...

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  3. Find the equation of hyperbola where, conjugate axis is 3 along Y-axis...

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  4. The length of the transverse axis of a hyperbola is 7 and it passes th...

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  5. One focus at (4,0) corresponding directrix x = 1 .

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  6. Distance between foci = 10 and eccentricity = 3/2

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  7. Conjugate axis = 10 and eccentricity = 6/5

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  8. One focus at (3,0) and eccentricity = 6/5

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  9. Find the equation of hyperbola whose conjugate axis = latus-rectum = 8...

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  10. e = 3/2 and distance between directrices = 8/3

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  11. Equation of the hyperbola in standard form which passes through the po...

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  12. Find the equation of hyperbola whose eccentricity = sqrt(2) and passi...

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  13. Eccentricity and latus-rectum of x^(2) - 3y^(2) = 36 are

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  14. For hyperbola, If transverse axis = conjugate axis , then e =

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  15. If transverse axis = 2 (latus-rectum ), then e =

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  16. If conjugate axis = 2 (latus-rectum ), then e =

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  17. If distance between foci = 3 (distance between directrices) . Then e =

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  18. Focus of the parabola y^(2) = 8x is a vertex of a hyperbola whose con...

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  19. Co-ordinates of point P ((pi)/(4)) on the hyperbola 25x^(2) - 9y^(2)...

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  20. Focal distances of a point P : x = 13 on 13 on 81x^(2) - 144 y^(2) ...

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