From a group of 5 men and 3 women, a committee of 4 persons is to be selected randomly. Find the probability that there is a majority of (i) men (ii) women.

Answer

(i) `therefore P(A) = (n(A))/(n(S)) = 35/70 = 1/2. `
(ii) ` therefore P(B) = (n(B))/(B(S)) = 5/70 = 1/14.`