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If 8 boys and 2 girls are to be seated ...

If 8 boys and 2 girls are to be seated in a row for a photograph, find the probability that the girls sit together.

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To find the probability that the two girls sit together when 8 boys and 2 girls are seated in a row for a photograph, we can follow these steps: ### Step 1: Calculate the total number of arrangements of 10 students The total number of students is 8 boys + 2 girls = 10 students. The total arrangements of these 10 students can be calculated using the factorial notation: \[ \text{Total arrangements} = 10! \] ### Step 2: Treat the two girls as a single unit To find the arrangements where the girls sit together, we can treat the two girls as a single entity or unit. This means we now have: - 8 boys - 1 unit (which consists of the 2 girls) So, we have a total of 8 boys + 1 unit = 9 units to arrange. ### Step 3: Calculate the arrangements of the 9 units The number of ways to arrange these 9 units (8 boys + 1 unit of girls) is given by: \[ \text{Arrangements of 9 units} = 9! \] ### Step 4: Arrange the girls within their unit Within their unit, the two girls can be arranged among themselves in: \[ \text{Arrangements of girls} = 2! \] ### Step 5: Calculate the number of favorable arrangements The total number of favorable arrangements where the girls sit together is the product of the arrangements of the 9 units and the arrangements of the girls within their unit: \[ \text{Favorable arrangements} = 9! \times 2! \] ### Step 6: Calculate the probability The probability that the girls sit together is given by the ratio of the number of favorable arrangements to the total arrangements: \[ P(\text{girls sit together}) = \frac{\text{Favorable arrangements}}{\text{Total arrangements}} = \frac{9! \times 2!}{10!} \] ### Step 7: Simplify the expression We know that \(10! = 10 \times 9!\). Thus, we can simplify the probability: \[ P(\text{girls sit together}) = \frac{9! \times 2!}{10 \times 9!} = \frac{2!}{10} = \frac{2}{10} = \frac{1}{5} \] ### Final Answer The probability that the girls sit together is: \[ \frac{1}{5} \]
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MARVEL PUBLICATION-PROBABILITY-MULTIPLE CHOICE QUESTIONS
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  2. Set of all possible outcomes of an experiment is called its

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  3. If S is the sample space of an experiment, than S must contain

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  4. If S(1),S(2) are the sample spaces of an experiment at the first two t...

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  5. If A an event in a sample space S, then

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  6. If P(A) denotes the probability of an event, then

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  7. Which of the following subsets of a sample space S represents an impos...

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  8. Probability of an impossible event

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  9. Which of the following subsets of a sample space S represents a certai...

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  10. The probability of a certain event is 0 (b) 1 (c) greater than 1...

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  11. A coin is tossed once. Write its sample space.

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  12. If one coin is tossed twice (or two coins tossed once), then the sampl...

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  13. If a coin is tossed three times (or three coins are tossed together...

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  14. If one coin is tossed n times (or n coins tossed once), then the numbe...

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  15. If one die is rolled once, then the sample space is

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  16. If one die is rolled n times (or n dice rolled once), then the number ...

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  17. If s is the total score when two dice are thrown once then

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  18. Indicate the probability of the following events an even number, in ...

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  19. If one die is rolled then find the probability of each of the followin...

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  20. Indicate the probability of the following events a prime number, in ...

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  21. Indicate the probability of the following events a number which is b...

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