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A class contains 10 men and 20 women, am...

A class contains 10 men and 20 women, among which half the men and half of the women have brown-eyes. Find the probability that a person, chosen at random, is a man or has brown eyes.

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To solve the problem, we need to find the probability that a person chosen at random is either a man or has brown eyes. We will use the principle of inclusion-exclusion to calculate this probability. ### Step-by-Step Solution: 1. **Determine the total number of people:** - There are 10 men and 20 women in the class. - Total number of people = Number of men + Number of women = 10 + 20 = **30**. 2. **Determine the number of men:** - The number of men in the class is **10**. 3. **Determine the number of people with brown eyes:** - Half of the men have brown eyes: - Brown-eyed men = 10 / 2 = **5**. - Half of the women have brown eyes: - Brown-eyed women = 20 / 2 = **10**. - Total number of people with brown eyes = Brown-eyed men + Brown-eyed women = 5 + 10 = **15**. 4. **Calculate the probability of selecting a man:** - Probability of selecting a man = Number of men / Total number of people = 10 / 30 = **1/3**. 5. **Calculate the probability of selecting a person with brown eyes:** - Probability of selecting a person with brown eyes = Number of people with brown eyes / Total number of people = 15 / 30 = **1/2**. 6. **Calculate the probability of selecting a man with brown eyes:** - Since we already counted the 5 brown-eyed men in both previous probabilities, we need to account for this overlap. - Probability of selecting a man with brown eyes = Number of brown-eyed men / Total number of people = 5 / 30 = **1/6**. 7. **Use the principle of inclusion-exclusion:** - Probability (Man or Brown Eyes) = Probability (Man) + Probability (Brown Eyes) - Probability (Man and Brown Eyes) - = (1/3) + (1/2) - (1/6). 8. **Finding a common denominator:** - The common denominator for 3, 2, and 6 is 6. - Convert each fraction: - (1/3) = 2/6, - (1/2) = 3/6, - (1/6) = 1/6. 9. **Combine the probabilities:** - Probability (Man or Brown Eyes) = 2/6 + 3/6 - 1/6 = (2 + 3 - 1) / 6 = 4/6 = **2/3**. 10. **Final answer:** - The probability that a person chosen at random is a man or has brown eyes is **2/3**.
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MARVEL PUBLICATION-PROBABILITY-MULTIPLE CHOICE QUESTIONS
  1. A class contains 10 men and 20 women, among which half the men and hal...

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  2. Set of all possible outcomes of an experiment is called its

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  3. If S is the sample space of an experiment, than S must contain

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  4. If S(1),S(2) are the sample spaces of an experiment at the first two t...

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  5. If A an event in a sample space S, then

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  6. If P(A) denotes the probability of an event, then

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  7. Which of the following subsets of a sample space S represents an impos...

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  8. Probability of an impossible event

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  9. Which of the following subsets of a sample space S represents a certai...

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  10. The probability of a certain event is 0 (b) 1 (c) greater than 1...

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  11. A coin is tossed once. Write its sample space.

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  12. If one coin is tossed twice (or two coins tossed once), then the sampl...

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  13. If a coin is tossed three times (or three coins are tossed together...

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  14. If one coin is tossed n times (or n coins tossed once), then the numbe...

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  15. If one die is rolled once, then the sample space is

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  16. If one die is rolled n times (or n dice rolled once), then the number ...

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  17. If s is the total score when two dice are thrown once then

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  18. Indicate the probability of the following events an even number, in ...

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  19. If one die is rolled then find the probability of each of the followin...

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  20. Indicate the probability of the following events a prime number, in ...

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  21. Indicate the probability of the following events a number which is b...

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