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Anita and Binita stand in a line with 7 ...

Anita and Binita stand in a line with 7 other people. What is the probability that there are 4 persons between them?

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To solve the problem of finding the probability that Anita and Binita stand in a line with 7 other people such that there are exactly 4 persons between them, we can follow these steps: ### Step 1: Understand the total number of people Anita and Binita are two people, and there are 7 other people. Therefore, the total number of people is: \[ \text{Total people} = 2 + 7 = 9 \] ### Step 2: Identify the arrangement conditions We want to find the arrangements where there are exactly 4 people between Anita and Binita. This means that if we denote the positions of Anita and Binita as A and B, the arrangement must look like: \[ A \_ \_ \_ \_ B \] or \[ B \_ \_ \_ \_ A \] where the underscores represent the 4 people in between. ### Step 3: Determine possible positions for A and B The positions of A and B can be represented in a line of 9 positions. The possible positions for A and B while maintaining 4 people in between them are: 1. A at position 1 and B at position 6 2. A at position 2 and B at position 7 3. A at position 3 and B at position 8 4. A at position 4 and B at position 9 This gives us a total of 4 valid arrangements for A and B. ### Step 4: Arrange the remaining people Once A and B are placed, we have 7 remaining positions (the 4 people in between and the 3 remaining positions) to fill with the other 7 people. The number of ways to arrange these 7 people in the remaining 7 positions is: \[ 7! \] ### Step 5: Account for the arrangement of A and B Since A and B can be arranged in two different ways (A can be before B or B can be before A), we multiply the arrangements by 2: \[ \text{Total favorable arrangements} = 4 \times 7! \times 2 \] ### Step 6: Calculate the total arrangements of all people The total number of arrangements of all 9 people (without any restrictions) is: \[ 9! \] ### Step 7: Calculate the probability The probability that there are exactly 4 persons between Anita and Binita is given by the ratio of favorable arrangements to total arrangements: \[ P(\text{4 persons between A and B}) = \frac{4 \times 7! \times 2}{9!} \] ### Step 8: Simplify the probability We know that: \[ 9! = 9 \times 8 \times 7! \] Thus: \[ P(\text{4 persons between A and B}) = \frac{4 \times 7! \times 2}{9 \times 8 \times 7!} = \frac{8}{72} = \frac{1}{9} \] ### Final Answer The probability that there are 4 persons between Anita and Binita is: \[ \frac{1}{9} \] ---
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MARVEL PUBLICATION-PROBABILITY-MULTIPLE CHOICE QUESTIONS
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  2. Set of all possible outcomes of an experiment is called its

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  3. If S is the sample space of an experiment, than S must contain

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  4. If S(1),S(2) are the sample spaces of an experiment at the first two t...

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  5. If A an event in a sample space S, then

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  6. If P(A) denotes the probability of an event, then

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  7. Which of the following subsets of a sample space S represents an impos...

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  8. Probability of an impossible event

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  9. Which of the following subsets of a sample space S represents a certai...

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  10. The probability of a certain event is 0 (b) 1 (c) greater than 1...

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  11. A coin is tossed once. Write its sample space.

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  12. If one coin is tossed twice (or two coins tossed once), then the sampl...

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  13. If a coin is tossed three times (or three coins are tossed together...

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  14. If one coin is tossed n times (or n coins tossed once), then the numbe...

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  15. If one die is rolled once, then the sample space is

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  16. If one die is rolled n times (or n dice rolled once), then the number ...

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  17. If s is the total score when two dice are thrown once then

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  18. Indicate the probability of the following events an even number, in ...

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  19. If one die is rolled then find the probability of each of the followin...

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  20. Indicate the probability of the following events a prime number, in ...

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  21. Indicate the probability of the following events a number which is b...

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