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If the plane x/2+y/3+z/4=1 cuts the coor...

If the plane `x/2+y/3+z/4=1` cuts the coordinate axes in `A, B,C,` then the area of triangle `ABC` is

A

`sqrt(29)` sq.u

B

`sqrt(41)` sq.u

C

`sqrt(61)` sq.u

D

`sqrt(39)`sq.u

Text Solution

Verified by Experts

The correct Answer is:
C
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