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The directionratios of the line which is...

The directionratios of the line which is perpendicular to the lines `(x-7)/2=(y+17)/(-3)=z-6 and x+5=(y+3)/2=(z-4)/(-2)` are (A) (4,5,7) (B) (4,-5,7) (C) (4,-5,-7) (D) (-4,5,7)

A

4,5,7

B

4,-5,7

C

4,-5,-7

D

`-4,5,7`

Text Solution

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The correct Answer is:
A
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Find the directions ratios of the line perpendicular to the lines (x-7)/(2) = ( y+ 7)/(-3) =(z-6)/(1) and (x+5)/(1) = (y+3)/(2)= (z-6)/(-2)

The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1 and (x+3)/(-36)=(y-3)/2=(z-6)/4 is (A) (21, 5/3, 10/3) (B) (2,10,4) (C) (-3,3,6) (D) (5,7,-2)

The point of intersection of the lines (x-5)/(3)=(y-7)/(-1)=(z+2)/(1) and (x+3)/(-36)=(y-3)/(2)=(z-6)/(4) is (A) (21,(5)/(3),(10)/(3))(B)(2,10,4)(C)(-3,3,6)(D)(5,7,-2)

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Find the angle between the lines (5-x)/(3)=(y+3)/(-4) ,z=7 " and " (x)/(1) =(1-y)/(2)=(z-6)/(2)

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Find the equation of plane containing the lines (x-5)/(4)=(y+7)/(4)=(z+3)/(-5) and (x-8)/(7)=(y-4)/(1)=(z-5)/(3) .

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MARVEL PUBLICATION-PLANE IN SPACE -PART B: MASTERING THE BEST ON LINE AND PLANE IN SPACE
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