`2y^4+y^3-14 y^2-19 y-6`

Divide: 3y^4-3y^3-4y^2-4y^2-4y-b y\ y^2-2y 2y^5+10 y^4+6y^3+y^2+5y+3\ b y\ 2y^3+1

The factors of 2y^3 - 5y^2 - 19y + 42 are :

Simplify 3y^(3) - [ 7y^(2) -{ - 2y^(3) -(2- 4y^(2))+6y -y^(2)}]

The polynomial 6y^4-19y^3-23y^2+10y+8 on factorization gives

Subtract : 5y^(4) - 3y^(3) + 2y^(2) + y - 1 from 4y^(4) - 2y^(3) - 6y^(2) - y + 5

How much is y^4 - 12y^2 + y + 14 " greater than " 17y^3 + 34y^2 -51y + 68 ?

If x ^(2) + y^(2) - 14 x - 6y - 6=0, then the maximum possible value of 3x + 4y is (where (x,y) is a point on the given curve)

(4x^3y - 6x^2 y^2 + 4xy^3 - y^4) can be expressed as :