Let `int((4+3x)dx)/((x^3-2x-4))=ln|(x-k)/(sqrt(x^2+k x+1))|+C ,`then`(k^2+l^2)=` (i) `8` (ii) `6` (iii) `0` (iv) `4`

Let int (4+3x)/(x^(3)-2x-4)= In|(x-k)/(sqrt(x^(2)+kx+1))|+C , then k^(2)+l^(2) is equal to

int(x^(2))/((x^(2)-4)^(3/2))dx=log|x+sqrt(x^(2)-4)|+A+c then A=

int(x^(2))/((x^(2)-4)^(3/2))dx=log|x+sqrt(x^(2)-4)|+A+c then A=

(i) int (dx)/sqrt(5+4x-x^2) (ii) int (dx)/sqrt(8+3x-x^2)

If (2x+3)/((x-3)(x+k))=9/(4(x-3))-1/(4(x+k)) " then "k=

If int (3x+4)/(x^3-2x-4) \ dx = log|x-2| + k logf(x) + c , then (i) f(x) = |x^2+2x+2| (ii) f(x) = x^2+2x+2 (iii) k=1/2 (iv) k=-1/4

If int (3x+4)/(x^3-2x-4) dx = log|x-2| + k logf(x) + c, then (i) f(x) = |x^2+2x+2| (ii) f(x) = x^2+2x+2 (iii) k=1/2 (iv) k=-1/4

int(-dx)/((x-2)sqrt(x^(2)-4x))=(1)/(k)cos ec^(-1)(f(x))+c, then (k,f(x))