The equation of normal to the curve, `x^(2//3)+y^(2//3)=a^(2//3)` at the point `(a,0)` is

Find the equation of the normal to the curve x^(2//3) + y^(2//3) = 2 at the point (1, 1).

The equation of normal to the curve y=x^(3)-2x^(2)+4 at the point x=2 is -

The equation of normal to the curve x^(2)+y^(2)-3x-y+2=0 at P(1,1) is

The equation of normal to the curve y^2 (2a-x) = x^3 at the point (a, -a) is... A) 2x-3y=5a B) x+2y+3a= 0 C) x-2y+3a= 0 D) x-2y =3a

The equation of normal to the curve x^(2)=3-2y at (1,1) is :

Find the equation of the normal to the curve ay^(2)=x^(3), at the point (am^(2),am^(3)). If normal passes through the point (a,0) then find the slope.

The equation of normal to the curve y=x^(3)-x^(2)-1 at the point whose abscissa is -2, is

The equation of the normal to the curve y^2=x^3 at x=8 is

The equation to the normal to the circle x^(2)+y^(2)-2x-2y=0 at the point (3,1) on it is

Find the equation of the normal to the curve a y^2=x^3 at the point (a m^2,\ a m^3) .