" 71.If "0.80" mole of "MnO_(2)" and "146g" of "HCl" react; "MnO_(2)+4HCl rarr MnCl_(2)+Cl_(2)+2H_(2)O" then "

KMnO_(4)+HCl rarr MnCl_(2)+X_((g))+Y+H_(2)O "X" is a

In the reaction MnO_(2)+4HCl to MnCl_(2)+2H_(2)O+Cl_(2)

If 1 g of HCl and 1 g of MnO_(2) heated together the maximum weight of Cl_(2) gas evolved will be : [MnO_(2) + 4HCl rarr MnCl_(2) + Cl_(2) + 2H_(2)O] :

If 1 g of HCl and 1 g of MnO_(2) heated together the maximum weight of Cl_(2) gas evolved will be : [MnO_(2) + 4HCl rarr MnCl_(2) + Cl_(2) + 2H_(2)O] :

If 1 g of HCl and 1 g of MnO_(2) heated together the maximum weight of Cl_(2) gas evolved will be : [MnO_(2) + 4HCl rarr MnCl_(2) + Cl_(2) + 2H_(2)O] :

Calcualte the mass of 95% pure MnO_(2) to produce 35.5 g of Cl_(2) as per the following reaction. MnO_(2) + 4HCl to MnCl_(2) + Cl_(2) + H_(2)O . (At. Mass of Mn = 55).

MnO_(2)+4HClrarrMnCl_(2)+Cl_(2)+2H_(2)O , In the reaction MnO_(2) acts as

Calculated the weight of MnO_2 required to produce 1.78 litre of Cl_2 at STP by following reaction MnO_2 + 4 HCl rarr MnCl_2 + Cl_2 + 2H_2O