[1+2(tan x+sec x)]^(1/2)

int (1+2) tan x(tan x+ sec x)}^(1//2) dx=

If int[1+2tan x(tan x+sec x)]^(1/2)dx=lambda log|(tan((x)/(2)+k))/(cos x)|+C then lambda K is equal to where 0 < x < (pi)/(2)

int {(1+2 tan x(tan x + sec x))^(1//2) dx is equal to

int {1+2 tan x (tan x + sec x )}^(1//2) dx=?

int {1+2 tan x (tan x + sec x )}^(1//2) dx=?

int{1+2 tan x(tanx+sec x)}^((1)/(2))dx=....

int{1+2tan x(tan x+sec x)}^((1)/(2))dx

Evaluate: int{1+2tan x(tan x+sec x))^((1)/(2))dx

(sec x sec y + tan x tan y) ^ (2) - (sec x tan y + tan x sec y) ^ (2) = 1 Prove it