sin alpha=(2xy)/(x^(2)+y^(2))rArr sec alpha-tan alpha=

(sin alpha+cos ec alpha)^(2)+(cos alpha+sec alpha)^(2)=tan^(2)alpha+cot^(2)alpha+7

If (sin alpha + "cosec" alpha )^(2) + ( cos alpha + sec alpha )^(2)=k+ tan^(2) alpha + cot^(2) alpha then k=

Let cos^-1(x/a)+cos^-1(y/b)=alpha thenAnswer the following questions (A) x^2/a^2+y^2/b^2+(2xy)/(ab) cos alpha = sin^2 alpha (B) x^2/a^2-y^2/b^2+(2xy)/(ab) cos alpha = sin^2 alpha (C) x^2/a^2+y^2/b^2-(2xy)/(ab) cos alpha = sin^2 alpha (D) x^2/a^2-y^2/b^2-(2xy)/(ab) cos alpha = sin^2 alpha

If 3 sec alpha- 5 tan alpha= k and 6 sec alpha+k tan alpha=5 then k^(2)=

If tan alpha=(x)/(y) , then show that x "cosec" (alpha)/(3)- y "sec" (alpha)/(3)=3 sqrt(x^(2)+y^(2))(0 lt alpha lt (pi)/(2))

tan^(2)alpha=1-p^(2) then sec alpha+tan^(3)alpha*cos ec alpha

The angle between the lines sin^(2) alpha.y^(2) -2xy.cos^(2) alpha + (cos^(2) alpha -1)x^(2) =0 is