[" 141.An electron of mass "m_(e)" and a proton of mass "m_(p)],[" are moving with the same speed.The ratio of their "],[" de-Broglie's wavelengths "(lambda_(e))/(lambda_(p))" is "]

An electron of mass m_(e) and a proton of mass m_(p) are moving with the same speed. The ratio of their de-Broglie wavelength lamda_(e)//lamda_(p) is

An electron of mass m_(e ) and a proton of mass m_(p) = 1836 m_(e ) are moving with the same speed. The ratio of their de Broglie wavelength (lambda_("electron"))/(lambda_("proton")) will be :

An electron of mass m_(e ) and a proton of mass m_(p) are accelerated through the same potential. Then the ratio of their de Broglie wavelengths is

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is

An electron (mass m_e ) and a proton (mass m_p ) are accelerated through the same potential, then lambda_e//lambda_p =

Proton and electron are moving along circular path with same speed. Find out ratioof debroglie wavelength that is (lambda_e)/(lambda_p) If m_p =1836 m_e

An electron, a doubly ionized helium ion (He^(+ +)) and a proton are having the same kinetic energy . The relation between their respectively de-Broglie wavelengths lambda_e , lambda_(He^(+)) + and lambda_p is :