off 2 tan x 1+tan x (cos2x+1) +1)(se sec" x + 2 tan x 2 then f(4) =

If f((2tanx)/(1+tan^2x))=((cos2x+1)(sec^2x+2tanx))/(2) then f(4) =

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+tan x))/(2) then f(x)=

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+2tan x))/(2) then f((1)/(4))=

If quad (2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)+2tan x))/(2) then f(4)=(i)11 (ii) 3(iii)0(iii)0

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+2tan x))/(2)

If quad (2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+2tan x))/(2) then domain and range of y=f(x) are given by

(tan 2x)/(1+ sec 2x) = tan x

(tan3x)/(tan x)=(2cos2x+1)/(2cos2x-1)

2 tan^(-1) (cos x) = tan^(-1) (2 cosec x)