A thin metallic wire of resistance `100 Omega` is immersed in a calorimeter containing 250 g of water at `10^@C` and a current of 0.5 ampere is passed through it for half an hour. If the water equivalent of the calorimeter is 10 kg, find the final temperature of water.

A thin metallic wire of resistance 100Omega is immersed in a calorimeter containing 250g of water at 10^(@)C and a current of 0.5 ampere is passed through it for half an hour. If the water equivalent of the calorimeter is 10g, find the rise of temperature.

An electrically heated coil is immersed in a calorimeter containing 360 g of water at 10^@C . The coil consumes energy at the rate of 90 W. The water equivalent of calorimeter and coil is 40 g. The temperature of water after 10 min is

A calorimeter contains 70.2 g of water at 15.3^@C . IF 143.7 g of water at 36.5^@C is mixed with it, the common temperature becomes 28.7^@C . The water equivalent of a calorimeter is

10 gm of ice at -20^(@)C is dropped into a calorimeter containing 10 gm of water at 10^(@)C , the specific heat of water is twice that of ice. When equilibrium is reached the calorimeter will contain:

An electrically heating coil was placed in a calorimeter containing 360g of water at 10^(@)C . The coil consumes energy at the rate of 70W . The water equivalent of calorimeter and coil is 40g . Find temperature of the water after 10min . Given specific heat of water = 1 cal//g.^(@)C, 1 cal = 4.2J .

50 g ice at 0^(@)C is dropped into a calorimeter containing 100 g water at 30^(@)C . If thermal . capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is

When 0.400 kg of water at 30^(@)C is mixed with 0.150 kg of water at 25^(@)C contained in a calorimeter, the final temperature is found to be 27^(@)C , find the water equivalent of the calorimeter.

A resistance coil of 60 omega is immersed in 42 kg of water. A current of 7 A is passed through it. The rise in temperature of water per minutes is :

When a calorimeter contains 40g of water at 50^(@)C , then the temperature falls to 45^(@)C in 10 minutes. The same calorimeter contains 100g of water at 50^(@)C , it takes 20 minutes for the temperature to become 45^(@)C . Find the water equivalent of the calorimeter.

A calorimeter contains 10 g of water at 20^(@)C . The temperature falls to 15^(@)C in 10 min. When calorimeter contains 20 g of water at 20^(@)C , it takes 15 min for the temperature to becomes 15^(@)C . The water equivalent of the calorimeter is