Thee lectron in the hydrogen atom circles around the proton with a speed of `2.18 xx 10^(6)ms^(-1)` in an orbit of radius `5.3 xx 10^(-11)m`. What magnetic field does it produce at the proton ?

An electron in the hydrogen atom circles around the proton with a speed of 2.18xx10^(6) m/s in an orbit of radius 0.53Å . The equivalent current is

The electron in a hydrogen atom circles around the proton with a speed of 2*18xx10^6ms^-1 in an orbit of radius 5*3xx10^-11m . Calcualte (a) the equivalent current (b) magnetic field produced at the proton. Given charge on electron 1*6xx10^-19C and mu_0=4pixx10^-7TmA^-1 .

The electron in hydrogen atom moves with a speed of 2.2xx10^(6)m//s in an orbit of radius 5.3xx10^(-11)cm . Find the magnetic moment of the orbiting electron.

The electron in the hydrogen atom is moving with a speed of 2.5 xx 10^(6) m/s in an orbit of radius 0.5 Å . Magnetic moment of the revolving electron is

The electron in the hydrogen atom is moving with a speed at 2.3xx10^(6) m//s in an orbit of radius 0.53 Å.The magnetic of the revolving electron is

If the electron of the hydrogen atom is moving with a speed of 2xx 10^(6) m//sec . In a circular orbit of radius 5 xx 10^(-11) meter , then calucalate current in the orbit .

The electron in a hydrogen atom is moving with a speed of 2*3xx10^6ms^-1 in an orbit of radius 0*53oversetoA . Calculate the magnetic moment of revolving electron.

The electron in a hydrogen atom circles around the proton in 1.5941xx10^(-18) s. the equivalent current due to motion of the electron is

In hydrogen atom, the electron is moving round the nucleus with velocity 2.18xx10^(6)ms^(-1) in an orbit of radius 0.528 A. The acceleration of the electron is .