An alpha particle is completing one circular round of radius `0*8m` in 2 seconds. Find the magnetic field at the centre of the circle. Electronic charge `=1*6xx10^(19)C`.

A helium nucleus makes full rotation in a circle of radius 0.8 m in 2.5 seconds. The value of magnetic field B at the centre of the circle will be

An electron makes ( 3 xx 10^5) revolutions per second in a circle of radius 0.5 angstrom. Find the magnetic field B at the centre of the circle.

A charge of 10^(-6)C is describing a circular path of radius 1cm making 5 revolution per second. The magnetic induction field at the centre of the circle is

The momentum of alpha -particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

A helium nucleus is moving in a circular path of radius 0.8m. If it takes 2s to complete one revolution. Find out magnetic field produced at the centre of the circle:

An alpha particle moves along a circular path of radius 2Å with a uniform speed of 2xx10^6ms^-1 . Calculate the magnetic field set up at the center of circular path.

A charged particle of mass m is moving with a speed u in a circle of radius r. If the magnetic field induction at the centre is B, the charge on the particle is

Calculate the charge on an alpha particle. Given on a proton =1.6xx10^(19) C .

A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is