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the velcoity -time relation of an electr...

the velcoity -time relation of an electron starting from rest is given by v=kt,where `h=2 ms^(-2)`.calculate the distance traversed in 3s.

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The velocity-time relation of an object starting from rest is given by v=3t . When "v" is in "m/s" and "t" in seconds. The distance traversed in "3" seconds is:

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Knowledge Check

  • The velocity-time relation of an electron starting from rest is given by u=id, where k=2m//s^(2) . The distance traversed in 3 sec is:-

    A
    9m
    B
    16m
    C
    27m
    D
    36m

  • A particle starts from rest and has velocity kt after time t. The distance travelled in time t is-

    A
    `kt^(2)`
    B
    `2kt^(2)`
    C
    `ksqrt(t)`
    D
    `1//2kt^(2)`

  • The velocity of particle at time t is given by the relation v=6t-(t^(2))/(6) . The distance traveled in 3 s is, if s=0 at t=0

    A
    `(39)/(2)`
    B
    `(57)/(2)`
    C
    `(51)/(2)`
    D
    `(33)/(2)`

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    A body starting from rest has an acceleration of 4ms^(-2) . Calculate distnce travelled by it in 5th second.

    The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

    An electron starting from rest has a velocity that increase linearly with time that is v=k t, wher k=2 m//s^(@) . What will be the distance covered in first 3 seconds of its motion ?

    The velocity of an object is changing with time and relation is given by the following equation. v=2t+3t^(2) Calculate the position of the object from the origin at t=2s.

    A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

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