The relation between time t and displacement x is `t = alpha x^2 + beta x,` where `alpha and beta` are constants. The retardation is

The relation between time and displacement x is t =alphax^(2) + betax , where alpha and beta are constants. (Take alpha =2 m^(-2) s, beta = 1m^(-1)s)

The instantaneous velocity of a particle moving in a straight line is given as v = alpha t + beta t^2 , where alpha and beta are constants. The distance travelled by the particle between 1s and 2s is :

The workdone by a gas molecule in an isolated system is given by, W = alpha beta^2 e^( - (x^2)/(alpha k T) ) , where x is the displacement, k is the Boltzmann constant and T is the temperature, alpha and beta are constants. Then the dimension of B will be :

A particle starts from rest with acceleration a = alpha t + beta t^2 where alpha and beta are constants. Find its displacement between t = 1 and t= 2 second.

The displacement x of a particle varies with time t as x = ae^(-alpha t) + be^(beta t) . Where a,b, alpha and beta positive constant. The velocity of the particle will.

In a typical combustion engine the work done by a gas molecule is given W=alpha^2betae^((-betax^2)/(kT)) where x is the displacement, k is the Boltzmann constant and T is the temperature. If alpha and beta are constants, dimensions of alpha will be:

A partical moves in a straight line as s=alpha(t-2)^(3)+beta(2t-3)^(4) , where alpha and beta are constants. Find velocity and acceleration as a function of time.

The magnitude of radius vector of a point varies with time as r = beta t ( 1- alpha t) where alpha and beta are positive constant. The distance travelled by this body over a closed path must be

Two waves travelling in a medium in the x-direction are represented by y_(1) = A sin (alpha t - beta x) and y_(2) = A cos (beta x + alpha t - (pi)/(4)) , where y_(1) and y_(2) are the displacements of the particles of the medium t is time and alpha and beta constants. The two have different :-