A liquid stands at the plane level in the U-tube when at reat. If areals of cross-section of both the limbs are equal, what will be the difference in height h of the two limbs of U-tube, when the sustem is given an acceleration a in horizontal direction towards right as shown?

A U - tube shown in Fig. containing two liquids of specific gravities rho_(1) and rho_(2) is given an acceleration a in the horizontal direction. What is the ratio rho_(1) : rho_(2) ?

When at rest, a liquid stands at the same level in the tubes shown in figure. But as indicated a height difference h occurs when the system is given an acceleration a towards the right. Here, h is equal to

A U-tube containing a liquid is accelerated horizontally with a constant acceleration a_0 . If the separation between the vertical limbs is l find the difference in the heights of the liquid in the two arms.

A U tube is supported with its limbs vertical and is partly filled with water. If the inner diameter of the limbs are 1cm,and 0.01 cm , respectively, what will be the difference in height of water in the two limbs? S.T. or water 70 xx 10^(-3) Nm^(-1) . Angle of contact , theta = 0^(@) .

A U tube is rotated about one of it's limbs with an angular velocity omega . Find the difference in height H of the liquid (density rho ) level, where diameter of the tube dlt lt L .

Fig, shows a U-tube of uniform cross-sectional area A accelerated with acceleration a as shown. If d is the seperation between the limbs. Then the difference in the levels of the liquid in the U-tube is

What will happen if there is a vacuum just above one limb of the U-tube half filled with liquid as shown in figure?

The area of cross section of the wider tube shown in figure is 900 cm^2 . If the boy standing on the piston weights 45 kg, find the difference in the levels of water in the two tubes.

The area of cross-section of the wider tube shown in fig., is 800cm^(2) . If a mass of 12 kg is placed on the massless piston, what is the difference in the level of water in two tubes.