If a number of little droplets of water each of radius r, coalesce to form a single drop of radius R, show that the rise in temperature will be given by
`Delta0=(3sigma)/(J)((1)/(r)-(1)/(R))`
Where `sigma` is the surface tension of water and J is the mechanical equivalent of heat.

If a number of little droplets of water, each of radius r , coalesce to form a single drop of radius R , show that the rise in temperature will be given by (3T)/J(1/r-1/R) where T is the surface tension of water and J is the mechanical equivalent of heat.

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

A number of droplets, each of radius r , combine to form a drop of radius R . If T is the surface tension, the rise in temperature will be

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n' droplets of equal of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to ( T = Surface tension of water )

n small droplets of water, each of radius r, coalesce ot form a single drop of radius R. Find (i) Velocity acquired by bigger drop if all the energy released is converted into kinetic energy. (ii) Rise in temperature. Take, surface tension of water =sigma Mechanical equivalent of heat =Q

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V . If T is the surface tension of the liquid, then