There is a soap bubble of radius `2.4 xx 10^(-4)m` in air cylinder at a pressure of `10^(5) N//m^(2)`. The air in the cylinder is compressed isothermal until the radius of the bubble is halved. Calculate the new pressure of air in the cylinder. Surface tension of soap solution is `0.08 Nm^(-1)`.

There is a soap bubble of radius 2.4 xx 10^(-4)m in air cylinder at a pressure of 10^(5) N//m^(2) . The air in the cylinder is compressed isothermal untill the radius of the bubble is halved. Calculate teh new pressure of air in the cylinder. Surface tension of soap solution is 0.08 Nm^(-1) .

There is a soap bubble of radius 2.4xx10^(-4)m in air cylinder which is originally at a pressure of 10^(5)(N)/(m^(2)) . The air in the cylinder is now compressed isothermally untill the radius of the bubble is halved. (the surface tension of the soap film is 0.08Nm^(-1)) . The pressure of air in the cylinder is found to be 8.08xx10^(n)(N)/(m^(2)) . What is the value of n?

Find the radius of the soap bubble if 44times10^(-6)J of work is done in flowing the soap bubble surface tension of soap solution 7times10^(-2)N/m

A soap bubble of radius 3cm is chaged with 9 nC (nanocoulomb) Find the excess pressure inside the bubble surface tension of soap solution =3xx10^(-3)m^(-1)

If the excess pressure inside a soap bubble of radius 5 mm is equal to the pressure of a water column of hight 0.8 cm, then the surface tension of the soap solution will be

What is the excess pressure inside a soap bubble of radius 5.00 mm ? Surface tension of soap solution is 2.50 xx 10^-2 Nm^-1

The work done in blowing a soap bubble of radius 0.2 m is (the surface tension of soap solution being 0.06 N/m )

The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is 3/100 N/m)