A piece of iron floats in mercury. Given...

A piece of iron floats in mercury. Given that the density of iron is `7.8xx10^(3) "kg"m^(-3)` and that of mercury is `13 xx 10^(3) "kgm"^(-3)`, Calculate the fraction of the volume of iron piece that remains outside the mercury.

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The correct Answer is:

`(0.43)`

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