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A block of mass 1 kg is moving towards a...

A block of mass 1 kg is moving towards a movablen vedge of amss 2 kg as shown in figure. All surfaces are smooth. When the block leaves the wedge from top, its velocity is making an angle `theta =30^(@)` with horizontal.

In the whole process let J be the magnitude of net impulse given to the block by the wedge, `J_(H)` its horizontal component and `J_(V)` its vertical component. Then

A

`J=(8)/(sqrt(3))`N-s

B

`J_(H)=4 N-s`

C

`J_(V)=(4)/(sqrt(3))` N-s

D

All of the above

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