The amount of work done in forming a soa...

The amount of work done in forming a soap bubble of radius `r = 1 cm` (surface tension `T = 3 xx 10^(-2) N//m`) is

A

`37.38 mu J`

B

`40.20 muJ`

C

`75.36 mu J`

D

`20.10 mu J`

Verified by Experts

The correct Answer is:

C

PROPERTIES OF MATTER
DC PANDEY|Exercise JEE Advanced|57 Videos
PROPERTIES OF MATTER
DC PANDEY|Exercise More than one option is correct|21 Videos
PROJECTILE MOTION
DC PANDEY|Exercise Level - 2 Subjective|10 Videos
RAY OPTICS
DC PANDEY|Exercise Integer type q.|15 Videos

Similar Questions

Explore conceptually related problems

The amount of work done in forming a soap film of size 10 cm x 10 cm is (Surface tension T=3xx10^(-2) N//m )

What is the work done in blowing a soap bubble of radius r and surface tension S?

The work done in blowing a soap bubble of radius r of the solution of surface tension T will be

The amount of work done in blowing up a soap bubble of radius 2 cm is [Given surface tension of soap solution = 4 xx 10^(-2) N m^(-1) ]

Excess pressure inside a soap bubble of radius r and surface tension T is

Amount of energy required to blow a bubble of radius 5 cm (surface tension of soap is 30xx10^(-2) N/m ) is

What will be the work done in blowing a soap bubble of radius 1 cm to 2 cm ? (If surface tension of soap solution is 25 xx 10^(-3) N/m)

The work done in blowing a soap bubble of radius 0.2 m is (the surface tension of soap solution being 0.06 N/m )

The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is 3/100 N/m)

What will be the work done in blowing out a soap bubble of radius 0.4 cm? The surface tension of soap solution is 30 xx 10^(-3)" N/m".