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A uniform rod of length L, has a mass ...

A uniform rod of length `L`, has a mass per unit length `lambda` and area of cross section `A`. The elongation in the rod is `l` due to its own weight, if it suspended form the celing of a room. The Young's modulus of the rod is

A

`(2 lambda g L^(2))/(Al)`

B

`(lambda g L^(2))/(2Al)`

C

`(2 lambda gL)/(Al)`

D

`(lambda gl^(2))/(AL)`

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The correct Answer is:
B
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