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2.3 gm Na is added to 6 gm of CH(3)CO OH...

2.3 gm Na is added to 6 gm of `CH_(3)CO OH`. The volume of `H_(2)` gas liberated at S.T.P.

A

1.12 L

B

2.24L

C

3.36 L

D

4.48 L

Text Solution

Verified by Experts

The correct Answer is:
1
`CH_(3)CO OH+Nato CH_(3)CO Ona+1/2 H_(2)`
`{:("1 mole","1mole","1/2 mole"),(60 g,23 g,11.2 lit),("0.1 mole","0.1 mole",=?),(=6g,2.3 g,1.12 lit):}`
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