Methanoic acid, the first member of carboxylic acid series, when warmed with concentrated sulphuric acid decompose in the following way and evolve carbon monoxide.

The driving force for this reaction lies in the fact that the `HC-=O^(+)` ion is very unstable acid and thus easily loses `H^(+)`.
If formic acid is replaced by benzoylformic acid, `C_6 H_5 COCOOH` the product formed will be

Options

A. `C_(6)H_(5)CO OH+CO+CO_(2)`
B. `C_(6)H_(5)CO OH+CO_(2)`
C. `C_(6)H_(5)CO OH+CO`
D. `C_(6)H_(5)CHO+CO_(2)`

Answer

C

Explanation

`C_(6)H_(5)COCO OH overset(H_(2)SO_(4))underset(Delta)toC_(6)H_(5)CO OH+CO`