Compound A, `C_4 H_8 O_2` has the following properties. (i) it reacts with sodium bicarbonate to liberate `CO_2` (ii) on fusion with alkali gives propane (iii) with `Ca(OH)_2` it gives product `C_8 H_(14) O_4 Ca` which on heating decomposes to diiso propyl ketone. Identify (A)

Explanation

(i) React with `NaHCO_(3)` to liberate `CO_(2)` and so -COOH group is present in it i.e. A is `C_(3)H_(7)CO OH`
(ii) `C_(3)H_(7)CO OH overset(NaOH+CaO)toC_(3)H_(8)+Na_(2)CO_(3)`
Thus (A) may be

Since both give propane on decaroxylation
(iii) However `C_(8)H_(14)O_(4)Ca` i.e., Ca salt of acid on heating

Gives di isopropyl ketone and thus chain in acid is also not straight. thus strucutre (II) is correct i.e. A is