Use differential to approximate `sqrt(36. 6)`

Explanation

To approximate \( \sqrt{36.6} \) using differentials, we will follow these steps:

### Step 1: Define the function
Let \( y = \sqrt{x} \).

### Step 2: Identify a nearby value of \( x \)
Choose \( x = 36 \) because it is close to \( 36.6 \) and we know \( \sqrt{36} = 6 \).

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