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The radius of the circle passing through...

The radius of the circle passing through the point (6,2) and having `x +y= 6` as its normal and `x+2y= 4` as its diameter is :

A

10

B

`2sqrt(5)`

C

6

D

4

Text Solution

Verified by Experts

The two diameters intersect at (8, -2) which is the centre of the circle. The circle passes through (6, 2).
`:. ` Radius`=sqrt((8-6)^(2)+(-2-2)^(2)) = sqrt(20)`
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