Find the equation of tangent to the curve given by`x=asin^3t ,y=bcos^3t` ... (1)at a point where `t=pi/2`.

Explanation

To find the equation of the tangent to the curve given by the parametric equations \( x = a \sin^3 t \) and \( y = b \cos^3 t \) at the point where \( t = \frac{\pi}{2} \), we will follow these steps:

### Step 1: Find the coordinates of the point at \( t = \frac{\pi}{2} \)

We substitute \( t = \frac{\pi}{2} \) into the parametric equations:

\[
x = a \sin^3\left(\frac{\pi}{2}\right) = a \cdot 1^3 = a
...