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If a clock with an uncompensated pendulu...

If a clock with an uncompensated pendulum of steel keeps correct time at `15^(@)C` how many seconds would it lose is 24 hours at a temperature of `25^(@)`? (Linear expansivity of steel `=12xx10^(-6)K^(-1)`)

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The correct Answer is:
`5.2s`
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NN GHOSH-EXPANSION OF SOLIDS-All Questions
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