A copper vessel weighting `190g` contains `300g` of water at `0^(@)C` and `50g` of ice at `0^(@)C`. Find the quantity of steam at `100^(@)C` that must be passed into the vessel to raise its temperature and that of its content by `10^(@)C` [Specific heat capacity of copper `=420 Jkg^(-1)K^(-1)L` (of steam) `=2250xx10^(3)Jkg^(-1)` and `L` (of ice )`=336xx10^(3)Jkg^(-1)`]

Answer

`12.27xx10^(-3)kg`