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How much work in joule is done in produc...

How much work in joule is done in producing heat necessary to convert 10g of ice at `-5^(@)C` into steam at `100^(@)C`? Given specificheat of ice `=0.5 cal g^(-1).^(@)C^(-1)`, latent heat of steam `= 540 cal g^(-1)`.

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When a man does exercise on a treadmill machine, work doen by him is supplied in the form of heat of an ice bath. Find how much he has to do to convert a piece of 5 gm of ice at -3^(@)C to steam at 100^(@)C .Given that the specific heat of ice is 0.5 cal/ gm^(@)C , latent heat of fusion of ice is 80 cal/gm and laten heat of vaporization of water is 540 cal/gm.

How many grams of ice at -14 .^(@)C are needed to cool 200 gram of water form 25 .^(@)C to 10 .^(@)C ? Take specific heat of ice =0.5 cal g^(-1) .^(@)C^(-1) and latant heat of ice = 80 cal g^(-1) .

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

How much work is needed to convert 5g of ice at -3^(@)C to steam at 100^(@)C ? (Sp. Heat capacity of ice =500 cal kg^(-1)K^(-1) sp. Latent heat of fusion of ice =80xx10^(3) cal kg^(-1) sp. Latent heat of vaporization of water =536xx10^(3)calkg^(-1) , and J=4.2 joules per calorie)

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