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How much work is needed to convert 5g of...

How much work is needed to convert `5g` of ice at `-3^(@)C` to steam at `100^(@)C`? (Sp. Heat capacity of ice `=500 cal kg^(-1)K^(-1)` sp. Latent heat of fusion of ice `=80xx10^(3) cal kg^(-1)` sp. Latent heat of vaporization of water `=536xx10^(3)calkg^(-1)`, and `J=4.2` joules per calorie)

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The correct Answer is:
`15067.5J`
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How much work in joule is done in producing heat necessary to convert 10g of ice at -5^(@)C into steam at 100^(@)C ? Given specificheat of ice =0.5 cal g^(-1).^(@)C^(-1) , latent heat of steam = 540 cal g^(-1) .

When a man does exercise on a treadmill machine, work doen by him is supplied in the form of heat of an ice bath. Find how much he has to do to convert a piece of 5 gm of ice at -3^(@)C to steam at 100^(@)C .Given that the specific heat of ice is 0.5 cal/ gm^(@)C , latent heat of fusion of ice is 80 cal/gm and laten heat of vaporization of water is 540 cal/gm.

Calculate the amount of head required to convert 1.00kg of ice at - 10^(@)C into stream at 100^(@)C at normal pressure Specific heat of ice = 2100J kg^(-1)K^(-1) intent heat of fusion of ice = 3.36 xx 10^(5)Jkg^(-1) specific heat capacity of water = 4200 Jkg^(-1)k^(-1) and latent head of vaporisation of water = 2.25 xx 10^(6)J kg^(-1)

A piece of ice of mass 50 g exists at a temperature of -20^(@)C . Determine the total heart required to covert it completely to steam at 100^(@)C . (Specific heat capacity of ice = 0.5 cal//g-^(@)C , specific latent heat of fusion for ice = 80 cal//g and specific latent heat of vaporization for water = 540 cal//g ).

In an energy recycling process, X g of steam at 100^(@)C becomes water at 100^(@)C which converts Y g of ice at 0^(@)C into water at 100^(@)C . The ratio of X/Y will be (specific heat of water ="4200" J kg"^(-1)K, specific latent heat of fusion =3.36xx10^(5)"J kg"^(-2) , specific latent heat of vaporization =22.68xx10^(6)" J kg"^(-1) )

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

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