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A bullet of lead melts when stopped by o...

A bullet of lead melts when stopped by obstacle. Assuming that 25 per cent of the heat is absorbed by the osbtacle, find the velocity of the bullet if its initial temperature is `27^(@)C`. (Melting point of lead `327^(@)C`, specific heat capacity of lead `=30 cal kg^(-1)K^(-1)` specific latent heat of fusion of lead `=6000 cal kg^(-1)` and `J=4.2` joules `cal^(-1)`)

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The correct Answer is:
`410ms^(-1)`
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A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g-^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead= 327^@C , specific heat of lead = 0.03 calories //gm//^@C , latent jeat of fusion of lead= 6calories//gm,J=4.2 joules //calorie ).

During the Indo-Pakistan war, a soldier observed that the lead bullet fired by him just melted, when stopped by an obstacle. Assuming that whole of the kinetic energy of bullet got converted into heat energy, calculate the velocity of the bullet. Given that initial temperature of the bullet = 47.6^(@)C . Melting point of lead 321^(@)C , specific heat of lead = 0.3 cal g^(-1).^(@)C^(-1) , latent heat of lead = 6 cal g^(-1) and J = 4.2 xx 10^(7) erg cal^(-1) .

With what velocity must a lead bullet at 50^(@)C strike against an obstacle in order that the heat produced by the arrest of the motion, is sufficient of melt it, assuming that all the heat produced remains within the bullet? (Specific heat capacity of lead =31cal kg^(-1)K^(-1) , melting point of lead =335^(@)C , specific latent heat capacity of lead =5370 cal kg^(-1)K^(-1) and J=4.2 joules cal^(-1) )

A lead bullet penetrates into a solid object and melts Assuming that 50% of its K.E. was used to heat it , calculate the initial speed of the bullet , The initial temp , of bullet is 27^(@)c and its melting point is 327^(@)C Latent heat of fasion of lead = 2.5 xx 10^(4) J kg^(-1) and sp heat capacity of lead = 1.25 J kg^(-1) K^(-1)

A 25 g bullet travelling at 400 m//s passes through a thin iron wall and emerges at a speed of 250 m/s. If the bullet absorbs 50 percent of the heat generated, a. what will be the temperature rise of the bullet? B. If the ambient temperature is 20^(@)C will the bullet melt, and if so how much? Given that specific heat of head is 0.03 "cal"//gm^(@)C and latent heat of fusion of lead is 6000 cal/kg. It is also given that melting pont of lead is 320^(@)C .

A lead bullet strikes against a steel plate with a velocity 200ms^-1 . If the impact is perfectly inelastic and the heat produced is equally shared between the bullet and the target, thent he rise in temperature of the bullet is (specific heat capacity of lead =125Jkg^-1K^-1 )

How many calories of heat will be absorbed when 2kg of ice at 0^(@)C melts ? ( Specific latent heat of fusion of ice = 80 cal //g )

How much work is needed to convert 5g of ice at -3^(@)C to steam at 100^(@)C ? (Sp. Heat capacity of ice =500 cal kg^(-1)K^(-1) sp. Latent heat of fusion of ice =80xx10^(3) cal kg^(-1) sp. Latent heat of vaporization of water =536xx10^(3)calkg^(-1) , and J=4.2 joules per calorie)

If a lead bullet be suddenly stopoed and all its energy be used to heat it, with what velocity must the bullet be fired to raise the temperature through 100^(@)C ? (Specific heat capacity of leat =31.4 calories per kg per kelvin and J=4.2 joules per calorie.)

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