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Two moles of helium gas (gamma=5/3) is i...

Two moles of helium gas `(gamma=5/3)` is initially tat temperature `t_(1)=27^(@)C` and occupies a volume of `V_(1)=20` litres. The gas is first expanded at consant pressure until the volume is doubled. Then it undergoes an adiabatic change until the temperature returns to its initial value. (i) Sketch the process on a `p-V` diagram (ii) what is the final volume and pressure of the gas, (iii) What is the work done by the gas?

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The correct Answer is:
`0.44xx10^(5)Pa;12.45kJ`
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