In the circuit shown in Fig. `emf E` , a resistance `R`, and coil inductances `L_(1)` and `L_(2)` are known. The internal resistance of the source and the coil resistances are neglible. Find the steady-state currents in the coils after the swich `Sw` was shorted.

Two coils of self inductance L_(1) and L_(2) are connected in parallel and then connected to a call of emf epsilon and internal resistance - R. Find the steady state current in the coils.

In the circuit, a battery of emf E, a resistance R and inductance coil L_(1) and L_(2) and switch S are connected as shown. In Fig. Initially the switch is open

A coil resistance R and inductance L is connected to a battery of emf E volt. The final current in the coil is

In the circuit shown in Fig. the emf of the sources is equal to xi = 5.0 V and the resistances are equal to R_(1) = 4.0 Omega and R_(2) = 6.0 Omega . The internal resistance of the source equals R = 1.10 Omega . Find the currents flowing through the resistances R_(1) and R_(2) .

A coil inductance L and resistance R is connected to a constant voltage source. How soon will the coil current attains eta(etalt1) fraction of the steady state value?

In fig the steady state current in 2omega resistance is

If L and R be the inductance and resistance of the choke coil, then indentify the correct statement

In the circuit shown, find the value of resistance R in terms of inductance L and capacitance C such that the current through the cell remains constant forever after the switch is closed.