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A thin non-conducting ring mass m, radiu...

A thin non-conducting ring mass `m`, radius `a`, carrying a charge `q` can rotate freely about its own axis which is vertical. At the initial moment the ring was at rest and no magnetic field was present. At instant `t = 0`, a uniform magnetic field is switched on which is vertically downwards and increase with time according to the law `B = B_(0)t`. Neglecting magnetism induced due to totational motion of the ring. Now answer the following questions.
The power developed by the forces acting on the ring, as a function of time :

Text Solution

Verified by Experts

The correct Answer is:
`(a) (B_(0)q)/(2m) (b) (q^(2)B_(0)^(2)a^(2)t)/(4m)`
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