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In a wire direct current i(1) and an AC ...

In a wire direct current `i_(1)` and an AC current `i_(2)=i_(20) sin omega`t is superposed. Find the RMS value of current in wire.

Text Solution

Verified by Experts

The correct Answer is:
`sqrt(i_(1)^(2)+(i_(20)^(2))/(2))`
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