Home
Class 12
PHYSICS
In a given AC circuit through a specific...

In a given AC circuit through a specific branch the current varies as a function of time given as
`i=i_(0)sin^(2)omegat " " 0 le omega t lt pi`
and `i=i_(0) sin omega t " " pi le omegat lt 2 pi`
Calculate the average current per cycle of this AC.

Text Solution

Verified by Experts

The correct Answer is:
`i_(0)((1)/(4)-(1)/(pi))`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT

    PHYSICS GALAXY - ASHISH ARORA|Exercise Practice Exercise 5.6|8 Videos
  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT

    PHYSICS GALAXY - ASHISH ARORA|Exercise Practice Exercise 5.7|11 Videos
  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT

    PHYSICS GALAXY - ASHISH ARORA|Exercise Practice Exercise 5.4|13 Videos
  • CURRENT ELECTRICITY

    PHYSICS GALAXY - ASHISH ARORA|Exercise All Questions|389 Videos
  • ELECTROSTATICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numberical Problems|73 Videos

Similar Questions

Explore conceptually related problems

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

In any AC circuit the emf (e) and the current (i) at any instant are given respectively by e= E_(0)sin omega t i=I_(0) sin (omegat-phi) The average power in the circuit over one cycle of AC is

If i_(1) = i_(0) sin (omega t), i_(2) = i_(0_(2)) sin (omega t + phi) , then i_(3) =

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

What is power dissipation in an a.c. circuit in which E = 230 sin (omega t + pi//2) , I = 10 sin omega t ?

An alternating voltage V = V_(0) sin omegat is applied across a circuit. As a result, a current I = I_(0) sin (omegat – p/2) flows in it. The power consumed per cycle is

Find the rms value of current from t = 0 to t=(2pi)/omega if the current varies as i=I_(m)sin omegat .